2y(3y-4)+24y=(7y-3)(2+y)

Question

2y(3y-4)+24y=(7y-3)(2+y)

Answer 1

2у(3у-4)+24у=(7у-3)(2+у)
6у²-8у+24у=14у+7у²-6-3у
6у²+16у=7у²+11у-6
6у²+16у-7у²-11у+6=0
-у²+5у+6=0
D=25-4*(-1)*6=49
x1=(-5+7)/(-2)=-1
x2=(-5-7)/(-2)=6