A) (5+2i)(2-5i)=10-25i+4i-10(i²)=10-21i+10=20-21i
б) (3+2i)²-2i(1-3i)=[3²+2×3×2i+(2i)²]-(2i+6)=(9+12i-4)-2i-6=5+12i-2i-6=-1+10i
в) (3-5i)/(1+2i)=[(3-5i)(1-2i)]/[(1+2i)(1-2i)]=(3-6i-5i-10)/(1+4)=(-7-11i)/5=
-1.4-2.2i
г) (2-5i)/(5+2i)-(4+3i)/(3-4i)=
[(2-5i)(5-2i)]/[(5+2i)(5-2i)]-[(4+3i)(3+4i)]/[(3-4i)(3+4i)]=
(10-4i-25i-10)/(25+4)-(12+16i+9i-12)/(9+16)=-29i/29-25i/25=-i-i=-2i