Решите пожалуйста :) (x+3)^2=(x-5)^2
[(x+3) - (x-5)]×[(x+3) + (x-5)] = 0 8(2x-2)=0 x = 1
(x + 3)^2 - (x - 5)^2 = 0 (x + 3 - x + 5)(x + 3 + x - 5) = 0 8 (2x - 2) = 0 2x - 2 = 0 2x = 2 x = 1