Помогите решить: log8(12)- log8 (15) + log8 (20)
log8(12)- log8 (15) + log8 (20)= log8(12/15)+log8(20)=log8(4/5*20)=log8(16)=log2^3(2^4)=4/3
log8(12)- log8 (15) + log8 (20) = log8((12/15)*20) = (1/3)log2 (16) = 4/3