Log2(2x-1)+log2(x+5)=log2 52-2

Question

Log2(2x-1)+log2(x+5)=log2 52-2

Answer 1

2x-1>0⇒x>0,5
x+5>0⇒x>-5
x∈(0,5;∞)
log(2)[(2x-1)(x+5)]=log(2)(52/4)
2x²+10x-x-5=13
2x²+9x-18=0
D=81+144=225
x1=(-9-15)/4=-6 не удов усл
x2=(-9+15)/4=1,5