З)(1+3x)/(1-2x) = (5-3x)/(1+2x)
1-2x≠0⇒x≠1/2 U 1+2x≠0⇒x≠-1/2
(1+2x)(1+3x)=(1-2x)(5-3x)
1+3x+2x+6x²-5+3x+2x-10x²=0
-4x²+10x-4=0
2x²-5x+2=0
D=25-16=9
x1=(5-3)/4=1/2 не удов усл
x2=(5+3)/4=2
и)(x-1)/(2x+3) -( 2x-1)/(3-2x )= 0
2x+3≠0⇒x≠-1,5 U 3-2x≠0⇒x≠1,5
(3-2x)(x-1)-(2x+3)(2x-1)=0
3x-3-2x²+2x-4x²+2x-6x+3=0
-6x²+x=0
-x(6x-1)=0
x=0
6x-1=0
6x=1
x=1/6