ПОМОГИТЕ!!!!!!!!!!!!!!!!!!!!!!!1 1.решите систему уравнений; 4у+20=2(3х-4у)-4...

№1
$\left \{ {{4y+20=2(3x-4y)-4} \atop {16-(5x+2y)=3x-2y}} \right. \left \{ {{4y+20=6x-8y-4} \atop {16-5x-2y=3x-2y}} \right. \left \{ {{12y-6x=-24|:6} \atop {-8x=-16|:(-8)}} \right. \left \{ {{2y-x=-4} \atop {x=2}} \right. 2y-2=-4 2y=-2 y=-1 2*(-1)-x=-4 -2-x=-4 -x=-2 x=2$
Ответ:(2;-1)

№2
$\left \{ {{2(2x-y)+3(2x-y)=32} \atop {5(2x-y)-2(2x+y)=4}} \right. \left \{ {{4x-2y+6x-3y=32} \atop {10x-5y-4x-2y=4}} \right. \left \{ {{10x-5y=32|:5} \atop {6x-7y=4}} \right. \left \{ {{2x-y=6.4} \atop {6x-7y=4}} \right. -y=6.4-2x y=2x-6.4 6x-7(2x-6.4)=4 6x-14x+44.8=4 -8x=-40.8 x=5.1 2*5.1-y=6.4 10.2-y=6.4 -y=-3.8 y=3.8$
Ответ:(5.1;3.8)