(4,35-(4/45+5/18):4,4):0,32 --------------------------------------- (20-0,68):8,05+2 2/45...

$\frac{(4.35-( \frac{4}{45}+ \frac{5}{18}):4.4):0.32}{(20-0.68):8.05+ 2\frac{2}{45} }$
$1) \frac{4}{45}+ \frac{5}{18}= \frac{8}{90}+ \frac{25}{90}= \frac{33}{90}= \frac{11}{30}$
$2) \frac{11}{30}: \frac{10}{44}= \frac{1}{12}$
$3) \frac{435}{100}- \frac{1}{12}= \frac{1305}{300}- \frac{25}{300}= \frac{1280}{300}= \frac{64}{15}$
$4) \frac{64}{15}: \frac{100}{32}= \frac{40}{3}$
$5)20-0.68=19.32$
$6)19.32:8.05=2.4$
$7) 2\frac{4}{10}+ 2\frac{2}{45}= \frac{24}{10}+ \frac{92}{45}= \frac{40}{9}$
$8) \frac{40}{3}: \frac{40}{9}=3$
Ответ: 3