Помогите решить (Ｔ＿Ｔ)

Решите задачу:

$\frac{(64^{9})^{2}}{84^{8}} = \frac{(2^{6})^{18}}{(2^{2} * 3 * 7)^{8}} = \frac{2^{108}}{2^{16} * 3^{8} * 7^{8}} = \frac{2^{108 - 16}}{3^{8} * 7^{8}} = \frac{2^{92}}{3^{8} * 7^{8}} = \frac{2^{92}}{21^{8}}$
$\frac{9^{8} * 25^{6}}{225^{6}} = \frac{(3^{2})^{8} * (5^{2})^{6}}{(3^{2} * 5^{2})^{6}} = \frac{3^{16} * 5^{12}}{3^{12} * 5^{12}} = \frac{3^{16}}{3^{12}} = 3^{16 - 12} = 3^{4} = 81$