Помогите пожалуйста номер 49 а, в, номер 50 а, в.

№49 а)
(8 - 6 $\frac{1}{4}$ ) * $\frac{1}{4}$ =
= 1 $\frac{3}{4}$ * $\frac{1}{4}$ =
= $\frac{7}{4}$ * $\frac{1}{4}$ =
= $\frac{7}{16}$

б)
( $\frac{5}{6}$ - $\frac{1}{2}$ ) * $\frac{1}{2}$ =
= ( $\frac{5}{6}$ - $\frac{3}{6}$ ) * $\frac{1}{2}$ =
= $\frac{2}{6}$ * $\frac{1}{2}$ =
= $\frac{1}{6}$

№ 50
а)
$\frac{6 - \frac{1}{ \frac{1}{2}- \frac{1}{3}} }{6 + \frac{1}{ \frac{1}{2} - \frac{1}{3}} } = \frac{6 - \frac{1}{ \frac{3}{6} - \frac{2}{6} } }{6 + \frac{1}{ \frac{3}{6} - \frac{2}{3} } } = \frac{6 - \frac{1}{ \frac{1}{6} } }{6 + \frac{1}{ \frac{1}{6} } } = \frac{6 - 6}{6 + 6} = 0$

б)
$2 + \frac{1}{1 + \frac{2}{1 + \frac{1}{3} } } = 2 + \frac{1}{1 + \frac{2}{1 \frac{1}{3} } } = 2 + \frac{1}{1 + 1 \frac{1}{2} } = 2 + \frac{1}{2 \frac{1}{2} } = 2 + \frac{1}{ \frac{5}{2} } = 2 + \frac{1}{5} = 2 \frac{1}{5}$
или 2,4