Решите уравнения. А) (Х+3)^2 -2 (х+3)-8=0 Б) 3^х+3^х-3=12
A x+3=a a²-2a-8=0 a1+a2=2 U a1*a2=-8 a1=-2⇒x+3=-2⇒x=-5 a2=4⇒x+3=4⇒x=1 Б 3^(x-3)*(27+1)=12 3^(x-3)*28=12 3^(x-3)=3/7 x-3=log(3)(3/7) x=3+1-log(3)7 x=4-log(3)7
Х²+6х+9-2х-6-8=0 х²+4х-5=0 (x+5)(x-1)=0 x1=-5 x2=1