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Решите задачу:

$(\frac{\sqrt{x}}{2}-\frac{1}{2\sqrt{x}})(\frac{x-\sqrt{x}}{\sqrt{x}+1}-\frac{x+\sqrt{x}}{\sqrt{x}-1}) = (\frac{(\sqrt{x})^2}{2\sqrt{x}}-\frac{1}{2\sqrt{x}})(\frac{\sqrt{x}(\sqrt{x}-1)}{\sqrt{x}+1}-\frac{\sqrt{x}(\sqrt{x}+1)}{\sqrt{x}-1}) = \\ = \frac{x-1}{2\sqrt{x}}\cdot\sqrt{x}\cdot(\frac{\sqrt{x}-1}{\sqrt{x}+1}-\frac{\sqrt{x}+1}{\sqrt{x}-1}) = \frac{x-1}{2}\cdot\frac{(\sqrt{x}-1)^2-(\sqrt{x}+1)^2}{(\sqrt{x}-1)(\sqrt{x}+1)} =$
$= \frac{x-1}{2}\cdot\frac{(\sqrt{x})^2-2\sqrt{x}+1-((\sqrt{x})^2+2\sqrt{x}+1)}{(\sqrt{x})^2-1^2} = \frac{x-1}{2}\cdot\frac{x-2\sqrt{x}+1-x-2\sqrt{x}-1)}{x-1} = \\ = \frac{-4\sqrt{x}}{2}=-2\sqrt{x}.$