Умножение к.ч (2+i)*(1-2i)= (3+i)*(3-1i)= (1-i)*(1+4i)= (4-i)*(4+2i)= (7+i)*(6-1i)=...

Question

Умножение к.ч

(2+i)*(1-2i)=
(3+i)*(3-1i)=
(1-i)*(1+4i)=
(4-i)*(4+2i)=
(7+i)*(6-1i)=
(6-i)*(7+4i)=
(9+i)*(1-5i)=
(1-i)*(3+3i)=
(2+i)*(5-7i)=
(7+i)*(3-9i)=

Answer 1

Вот пять щя ищю пять решу)))

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