Решите уравнение 2^х+1 + 2^х+2 = 36
Решение 2^(х+1) + 2^(х+2) = 36 ОДЗ: x + 1 > 0, x > - 1 x + 2 > 0, x > - 2 x ∈ (- 1;+ ∞) 2*(2^x) + 2² * (2^x) = 36 6*(2^x) = 36 2^x = 6 log₂ (2^x) = log₂ 6 x = log₂ 6 x = log₂ 2 + log₂ 3 x = 1 + log₂ 3