1/ (3x+1)/(x+4)>0 x≠4
------- -4 -------------------- -1/3----------------4---------
+ - +
x∈(-∞;-4)∪(-1/3;4)∪(4;∞)
log₂(2x+1)=log₂3+1=log₂3+log₂2=log₂6
2x+1=6 2x=5 x=2.5
log₃(12-5x)=2 12-5x=9 5x=3 x=3/5=0.6
log₃²x+log₃x-2=0 по т.Виета log₃x= -2 x=1/9 или logₐx=1 x=3