1)
a) √(x+2)=√(2x-3)
ОДЗ:
x+2≥0 x≥-2
2x-3≥0 2x≥3 x≥1,5
x+2=2x-3
x-2x=-3-2
-x=-5
x=5
б) x=∛(x³-x²-8x+20)
x³=x³-x²-8x+20
x³-x³+x²+8x-20=0
x²+8x-20=0
D=8²-4*(-20)=64+80=144
x=(-8-12)/2=-10 x=(-8+12)/2=2
2.
log₅x=1/2log₅144+2log₅3-3log₅3
log₅x=log₅√144-log₅3
log₅x=log₅12-log₅3
log₅x=log₅(12/3)
log₅x=log₅4
x=4
log₃x=1/3log₃27+4log₃2-2log₃2
log₃x=log₃∛27+2log₃2
log₃x=log₃3+log₃2²
log₃x=log₃(3*4)
log₃x=log₃12
x=12
5.
