Решите 4 пожалуйста (если можно подробно)

$\frac{2 \sqrt{2}-5 }{ \sqrt{2} -1} + \frac{3\sqrt{6}-\sqrt{300}}{\sqrt{3}} = \frac{2\sqrt{2}-5}{\sqrt{2}-1} + \frac{3\sqrt{3}*\sqrt{2}-\sqrt{3}*\sqrt{100}}{\sqrt{3}} = \\ \\ = \frac{2\sqrt{2}-5}{\sqrt{2}-1} + \frac{\sqrt{3}*(3\sqrt{2}-10)}{\sqrt{3}} = \frac{2\sqrt{2}-5}{\sqrt{2}-1} +3\sqrt{2}-10= \\ \\ =\frac{2\sqrt{2}-5+(3\sqrt{2}-10)*(\sqrt{2}-1)}{\sqrt{2}-1} = \frac{2\sqrt{2}-5+6-3\sqrt{2}-10\sqrt{2}+10}{\sqrt{2}-1} = \\ = \frac{-11\sqrt{2}+11}{\sqrt{2}-1}= \frac{-11(\sqrt{2}-1)}{\sqrt{2}-1} =- 11$

Ответ: 11