Y=46sinx-46x+p/4. найти наименьшее значение функции на отрезке [-p/2;p/2}
Y=46sinx-46x+π/4 y`=46cosx-46 46cosx-46=0 46cosx=46 cosx=1 x=2πn n=0 x=0∈[-π/2;π/2] y(-π/2)=46sin(-π/2)-46*(-π/2)+π/4=-46+23π+π/4≈27 наиб y(0)=46sin0-46*0+π/4=π/4≈0,8 y(π/2)=46sinπ/2-46*π/2+π/4=46-23π+π/4≈-25,4 наим