Решите уравнение 2(x-3)/⅓=4

$\frac{2x-3}{ \frac{1}{3} } =4 \\ \\ 2x-3= 4* \frac{1}{3} \\ \\ 2x = 1 \frac{1}{3} +3 \\ \\ 2x = 4 \frac{1}{3} \\ \\ x= 4 \frac{1}{3} :2 = \frac{13}{3} * \frac{1}{2}= \frac{13}{6} \\ \\ x= 2 \frac{1}{6}$

проверим:
$\frac{2*2 \frac{1}{6 } -3}{ \frac{1}{3} } = 4 \\ \\ \frac{ \frac{2*13}{1*6}-3 }{ \frac{1}{3} } =4 \\ \\ (4 \frac{1}{3} -3 ) : \frac{1}{3} =4 \\ \\ 1\frac{1}{3} : \frac{1}{3} =4 \\ \\ \frac{4}{3} * \frac{3}{1} =4 \\ \\ 4=4$