F
1)3/(x-2)²+2/[(x-2)(x+2)]=(3x+6+2x-4)/[(x-2)²(x+2)]=(5x+2)/[(x-2)²(x+2)]
2)(5x+2)/[(x-2)²(x+2)]*(x-2)²=(5x+2)/(x+2)
3)(5x+2)/(x+2)-5x/(x+2)=(5x+2-5x)/(x+2)=2/(x+2)
b
1)2/(x-3)²+3/[(x-3)(x+3)]=(2x+6+3x-9)/[(x-3)²(x+3)]=(5x-3)/[(x-3)²(x+3)]
2)(5x-3)/[(x-3)²(x+3)]*(x-3)²=(5x-3)/(x+3)
3)(5x-3)/(x+3)-5x/(x-3)=(5x-3-5x)/(x+3)=-3/(x+3)