Log2(x+4)+log2(x+1)=1+log2 5
Log2 (x+4) + log2 (x+1)=1+log2 5, (x bolše čem -1) log2 (x+4) + log2 (x+1) = log2 2 +log2 5 log2 (x+4)(x+1) = log2 (2.5) (x+4)(x+1)=10 x²+5x+4=10 x²+5x-6=0 (x+6)(x-1)=0 a)x+6=0, x=-6 net rešeniem! b)x-1=0, x=1 Otvet: x=1 ========