√2cos (2x/3+п/4)=1 Помогите пожалуйста!!!
Cos(2x/3+π/4)=1/√2 2x/3+π/4=+-arcos(1/√2)+2πn, n∈Z 2x+π/4=π/4+2πn, n∈Z или 2x+π/4=-π/4+2πn, n∈Z 2x=2πn, n∈Z 2x==-2π/4+2πn, n∈Z x=πn, n∈Z x=-π/2+πn, n∈Z ответ: х1=πn, n∈Z, x2=-π/2+πn, n∈Z