X^2+(x^2+20)=22 .....

Question

X^2+(x^2+20)=22 .....

Answer 1

Вроде так должно быть .....

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Answer 2

X^4+20x^2-22=0
x^2=t
t^2+20t-22=0
D=400+22*4=488
t1=-20+sqrt488\2
t2=-20-sqrt488\2

Comments

x^2=-20+sqrt488\2