5(9-x^2)=x(x-3) ПОМОГИТЕ ПЖ

Question

5(9-x^2)=x(x-3) ПОМОГИТЕ ПЖ

Answer 1

5(3 - x)(3 + x) - x (x - 3) = 0 
- 5(x - 3)(x + 3) - x (x - 3) =  0
5 (x - 3)(x + 3) + x(x - 3) = 0
(x - 3)(5x + 15 + x) = 0 
(x - 3)(6x + 15) = 0 

x - 3 = 0 
x =  3

6x + 15= 0 
x = - 2,5