Решите : 1)32,4:(7,06икс-101,2)×1,8=1,458! 2)12-7 21/29+ ×+4 23/29=12 2/29...

Решите задачу:

$\frac{32,4}{7,06x-101,2}*1,8=1,458\\7,06x-101,2=32,4:(\frac{1,458}{1,8})=32,4:0,81\\7,06x=40+101,2\\x=\frac{141,2}{7,06}=20$

$12-7\frac{21}{29}+x+4\frac{23}{29}=12\frac{2}{29}\\x=12\frac{2}{29}+7\frac{21}{29}-4\frac{23}{29}-12=19\frac{23}{29}-4\frac{23}{29}-12=15-12=3$

$\frac{0,95x-1,82}{1,7}=3,4\\0,95x=3,4*1,7+1,82=5,78+1,82\\x=\frac{7,6}{0,95}=8$

$\frac{24,8}{6,08x-20,8}*2,7=1,674\\6,08x-20,8=24,8:(\frac{1,674}{2,7})=24,8:0,62\\6,08x=40+20,8\\x=\frac{60,8}{6,08}=10$