5/7:(6/7x+3/7)-1/2=1/6 РЕШИТЕ УРАВНЕНИЕ

Решите задачу:

$\frac{5}{7}:(\frac{6}{7}x+\frac{3}{7})-\frac{1}{2}=\frac{1}{6}\\\frac{\frac{5}{7}}{\frac{6}{7}x+\frac{3}{7}}=\frac{1}{6}+\frac{1}{2}\\\frac{\frac{5}{7}}{\frac{3}{7}(2x+1)}=\frac{1}{6}+\frac{3}{6}\\\frac{\frac{5}{7}:\frac{3}{7}}{\frac{3}{7}:\frac{3}{7}(2x+1)}=\frac{1}{6}+\frac{3}{6}\\\frac{\frac{5}{7}*\frac{7}{3}}{2x+1}=\frac{4}{6}\\\frac{\frac{5}{3}}{2x+1}=\frac{2}{3}\\\frac{5}{3}*3=2(2x+1)\\5=4x+2\\4x=5-2=3\\x=\frac{3}{4}=0,75$