A)log(2/3) (2-5x)0; x<0,4<br> 2/3<1; 2-5x>(2/3)^(-2)
-5x>9/4-2; -5x>0,25; x<-0,05<br>б) log(5) (x+13)-13; x>5 x>5
5>1; x+130
x^2-3x-28=0; D=9-4*(-28)=9+112=121=11^2; x1=(3-11)/2=-4; x2=7
+ - +
---------- -4-----------7------------------>x
/////////// /////////////////// x (-∞;-4)∪(7;+∞)
x>5! x(7;+∞)
Ответ(7;+∞)