1
f`(x)=3x²-12=3(x²-4)=3(x-2)(x+2)
3(x-2)(x+2)/[(x-4)(x+6)]≤0
+ _ + _ +
------------(-6)-------------[-2]--------[2]----------(4)------------
x∈(-6;-2] U [2;4)
2
а)f`(x)=12x²-6x
б)f`(x)=6/x³+1/2√x
в)y`=3(2x-1)²*2=6(2x-1)²
3
f(x)=1/x² x0=1
f(1)=1
f`(x)=-2/x³
`f(1)=-2
Y=1-2(x-1)=1-2x+2=-2x+3
4
v(t)=x`(t)=5-2t
v(1)=5-2=3