(х-1)(х^2-7х+6)=4(х-6) Решите пожалуйста
(x - 1) * (x - 6)(x - 1) = 4 (x - 6) (x - 1)^2 (x - 6) - 4 (x - 6) = 0 (x - 6) ((x - 1)^2 - 4) = 0 (x - 6)( x - 1 - 2)*(x - 1 + 2) = 0 (x - 6)( x - 3) (x + 1) = 0 x - 6 = 0 x = 6 x - 3 = 0 x = 3 x + 1 = 0 x = - 1 Ответ - 1; 3; 6