Решите пожалуйста 805 а

Решите задачу:

$7 \frac{1}{4} x+x-2 \frac{11}{12} x+1 \frac{2}{3} x=5 \frac{3}{5} \\ \\ \\ 7 \frac{1*3}{4*3} x+ \frac{12}{12} x- \frac{12*2+11}{12} x+1 \frac{2*4}{3*4} x=5 \frac{3}{5} \\ \\ \\ \frac{12*7+3}{12} x+\frac{12}{12}x- \frac{35}{12} x+ \frac{20}{12} x=5 \frac{3}{5} \\ \\ \\ ( \frac{87}{12} +\frac{12}{12}- \frac{35}{12} + \frac{20}{12} )x=5 \frac{3}{5} \\ \\ \\ \frac{87+12-35+20}{12} x= \frac{5*5+3}{5} \\ \\ \\ \frac{84}{12} x=\frac{28}{5} \\ \\ \\ 7x=\frac{28}{5} \\ \\ \\$

$x=\frac{28}{5}:7 \\ \\ \\ x=\frac{28}{5}* \frac{1}{7} \\ \\ \\ x=\frac{28:7}{5}* \frac{1}{7:7} \\ \\ \\ x=\frac{4}{5}* \frac{1}{1} \\ \\ \\x= \frac{4}{5}$