Решите уравнение : 2x^4+5x^3-5x-2=0
2x^4 + 5x³ - 5x -2 = 0 2(x⁴-1) + 5x(x²-1) = 0 2(x²-1)(x²+1) + 5x(x²-1) = 0 (2(x²+1) + 5x)(x²-1) = 0 (2x² + 5x + 2)(x²-1) = 0 x² - 1 = 0 x = 1; x = -1 2x²+5x +2 = 0 x1 = -2; x2 = 0,5