Решите уравнение, пожалуйста :)
4(1-cos4x)²/4+3cos4x-1=0 1-2cos4x+cos²4x+3cos4x-1=0 cos4x+cos²4x=0 cos4x(1+cos4x)=0 cos4x=0⇒4x=π/2+πk⇒x=π/8+πk/4,k∈z cos4x=-1⇒4x=π+2πn⇒x=π/4+πn/2,n∈z
4sin⁴2x+3cos4x-1=0 4(1-cos4x)²/4+3cos4x-1=0 1-2cos4x+cos²4x+3cos4x-1=0 cos4x+cos²4x=0 cos4x(1+cos4x)=0 cos4x=0 или cos4x=-1 4x=П/2+Пn 4x=П+2Пm x=П/8+Пn/4,n ∈ Z x=П/4+Пm/2,m ∈ Z Ответ:П/8+Пn/4, П/4+Пm/2, n,m ∈ Z