{x>0; x≠1
{log(2)x +2*(1/log(2) x)<3log(2)x<br>
1)log(2)x≠0; ( log(2)x)^2+2<3; log(2) x>0
log^2 (2)x-3log(2)x +2 <0<br> y=log(2)x; y^2-3y+2<0; D=9-8=1; y1=(3-1)/2=1;y2=2<br> + - +
-------------------------1---------------2------------->y
//////////////////// 122)log(2)x<0; log^2(2)x+2>3log(2)x; log^2(2)x-3log(2)x+2>0;
log(2)x⊂(0;1)∪(2;+∞) ;
0x⊂(1;2)∪(2;4)∩(4+∞)-это ответ.