Решите уравнение (4y+3)-(10y+11)=7+(13-4y)
4y+3-10y+11=7+13-4y -2y=6 y=-3
( 4y + 3 ) - ( 10y + 11 ) = 7 + (13 - 4y ) 4y + 3 - 10y - 11 = 7 + 13 - 4y 4y - 10y + 4y = 7 + 13 + 11 - 3 -2y = 28 y = -14