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Question 1

Question 2

$\frac{(4\frac{5}{12}-3\frac{7}{18}):9,25+\frac{5}{6}}{(0,4+\frac{1}{8}+0,75)*\frac{2}{3}}$ = $\frac{(\frac{53}{12}-\frac{61}{18}):9\frac{1}{4}+\frac{5}{6}}{(0,4+0,125+0,75)*\frac{2}{3}}$ = $\frac{(\frac{159}{36}-\frac{122}{36}):\frac{37}{4}+\frac{5}{6}}{1,275*\frac{2}{3}}$ = $\frac{\frac{37}{36}*\frac{4}{37}+\frac{5}{6}}{0,425*2}$ = $\frac{\frac{1}{9}+\frac{5}{6}}{0,85}$ = $\frac{\frac{2}{18}+\frac{15}{18}}{0,85}$ = $\frac{\frac{17}{18}}{0,85}$ = $\frac{17}{18}:0,85$ = $\frac{17}{18}:\frac{85}{100}$ = $\frac{17}{18}:\frac{17}{20}$ = $\frac{17}{18}*\frac{20}{17}$ = $\frac{20}{18}$ = $1\frac{2}{18}$ = $1\frac{1}{9}$

$\frac{3\frac{7}{15}*0,25+\frac{5}{6}-1\frac{2}{5}}{5,4:(\frac{3}{20}+0,75)}$ = $\frac{\frac{52}{15}*\frac{1}{4}+\frac{5}{6}-\frac{7}{5}}{5\frac{2}{5}:(\frac{3}{20}+\frac{3}{4})}$ = $\frac{\frac{13}{15}+\frac{5}{6}-\frac{7}{5}}{\frac{27}{5}:(\frac{3}{20}+\frac{15}{20})}$ = $\frac{\frac{52}{60}+\frac{50}{60}-\frac{7}{5}}{\frac{27}{5}:\frac{18}{20}}$ = $\frac{\frac{102}{60}-\frac{84}{60}}{\frac{27}{5}*\frac{20}{18}}$ = $\frac{\frac{18}{60}}{27*\frac{4}{18}}$ = $\frac{\frac{3}{10}}{3*2}$ = $\frac{3}{10}:6$ = $\frac{3}{10}*\frac{1}{6}$ = $\frac{1}{10}*\frac{1}{2}$ = $\frac{1}{20}$ = 0,05