(х-1)(х-4)(х+7)=х(х+1)^2

Question

(х-1)(х-4)(х+7)=х(х+1)^2

Answer 1

(x+7)(x^2-5x+4)=x(x^2+2x+1)
x^3-5x^2+4x+7x^2-35x+28=x^3+2x^2+x
x^3-5x^2+4x+7x^2-35x+28-x^3-2x^2-x
-32x=-28
x=(-28)/(-32)
x=0,875