Решите
X³+2x²-3x=x(x²+2x-3)=x(x+3)(x-1) x²+2x-3=0 x1+x2=-2 U x1*x2=-3⇒x1=-3 U x2=1 (x³+2x²-3x)/(x²+3x)=x(x+3)(x-1)/[x(x+3)=x-1