найти одз!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!
y=√ 2-3x
2 - 3х
2 – 3х ≥ 0
- 3х ≥ -2
х≤ 2/3
хϵ ( - ∞; 2/3]
y=√ 2-3x 2-3x>0 -3x>-2 x<2/3<br>ответ (-∞;2.3)