1) 3.4+2y=7(y-2.3) 2) 0.2(7-2y)=2.3-0.3*(y-6)

Question

1) 3.4+2y=7(y-2.3)
2) 0.2(7-2y)=2.3-0.3*(y-6)

Answer 1

3,4+2у=7(у-2,3)
3,4+2у=7y-16,1
3,4+16,1=7y-2y
19,5=5y
Y=3,9