(6)\(х²-36) - (3)\(х²-6х) +(х-12)\(х²+6х) = 0

Question

(6)\(х²-36) - (3)\(х²-6х) +(х-12)\(х²+6х) = 0

Answer 1

6/(x-6)(x+6)-3/[x(x-6)]+(x-12)/[x(x+6)]=0
x≠0;x≠6;x≠-6
6x-3(x+6)+(x-6)(x-12)=0
6x-3x-18+x²-12x-6x+72=0
x²-15x+54=0
x1+x2=15 U x1*x2=54
x1=6 не удов усл
х=9