Al₂O₃ + HCl⇒ m(Al₂O₃)20.4г m(HCl)-?

Question

Al₂O₃ + HCl⇒ m(Al₂O₃)20.4г
m(HCl)-?

Answer 1

Al2O3 + 6HCl = 2AlCl3 + 3H2O
M Al2O3 = 2*27 + 3-16 = 102г/моль v Al2O3 = 20.4/102 = 0.2моль
M HCl = 36.5 г/ моль v HCl = 0.2*6 = 1.2 моль по уравнению m HCl = 36.5*1.2 = 7.3 г