1
x(x-1)/[(x-2)(x+2)]>0
x=0 x=1 x=2 x=-2
+ _ + _ +
---------------(-2)------------(0)------------(1)--------------(2)------------------
x∈(-∞;-2) U (0;1) U (2;∞)
2
x²/[x(x+3)]+(2-x)/(x+3)-(5-x)/x<0<br>(x²+2x-x²-5x-15+x²+3x)/[x(x+3)]<0<br>(x²-15)/[x(x+3)]<0<br>x²-15=0
x²=15
x=-√15
x=15x=0
x+3=0
x=-3
+ _ + _ +
---------------(-√15)------------(-3)------------(0)--------------(√15)------------------
x∈(-√15;-3) U (0;√15)