Дробь 3/(x-2)^2+дробь 5/(x-2)-8=0

$\frac{3}{(x-2)^2}+\frac{5}{x-2}-8=0\\\\\frac{3}{(x-2)^2}+\frac{5(x-2)}{(x-2)^2}-\frac{8(x-2)^2}{(x-2)^2}=0\\\\\frac{3+5(x-2)-8(x-2)^2}{(x-2)^2}=0\\\\\frac{3+5x-10-8(x^2-4x+4)}{(x-2)^2}=0\\\\\frac{3+5x-10-8x^2+32x-32}{(x-2)^2}=0\\\\\frac{-8x^2+37x-39}{(x-2)^2}=0\\\\ \left \{ {{-8x^2+37x-39=0} \atop {(x-2)^2 \neq 0}} \right. \left \{ {{-8x^2+37x-39=0} \atop {x-2 \neq 0}} \right. \left \{ {{-8x^2+37x-39=0} \atop {x \neq 2}} \right.$
О Отдельно решим первое уравнение системы
$-8x^2+37x-39=0|:(-1)\\8x^2-37x+39=0\\D=(-37)^2-4*8*39=1369-1248=121\\x_{1}=\frac{37+11}{16}=\frac{48}{16}=3\\\\x_{2}=\frac{37-11}{16}=\frac{26}{16}=\frac{13}{8}=1\frac{5}{8}$
Вернемся в систему
$1.\left \{ {{x=3} \atop {x \neq 2}} \right=\ \textgreater \ x=3\\\\2,\left \{ {{x=1\frac{5}{8}} \atop {x \neq 2}} \right.=\ \textgreater \ x=1\frac{5}{8}$
$Otvet:x=3,x=1\frac{5}{8}$