(cos2x+cos4x)/(sin2x+sin4x)

Question

(cos2x+cos4x)/(sin2x+sin4x)

Answer 1

(cos(2*x)+cos(4*x))/(sin(2*x)+sin(4*x))= (4*cos(x)^3-3*cos(x))/((4*cos(x)^2-1)*sin(x))=ctg(3*x)