Решите систему уравнений
2x^2+4y^2=24 |*2 4x^2+8y^2=24x 4x^2+8y^2=48 4x^2+8y^2=24x 48-24x=0 -24x=-48 x=2 2*2^2+4y^2=24 2*4+4y^2=24 8+4y^2=24 4y^2=24-8 4y^2=16 y^2=4 y=2 Ответ: (2;2)