sin2x cosx-sinx cos2x=1

Question

sin2x cosx-sinx cos2x=1

Answer 1

                                              Решение:

 

 

2sinxcos^2x-sinxcos2x=1
sinx(2cos^2x-cos^2x+sin^2x)=1
sinx(cos^2x+sin^2x)=1
sinx=1
x=П/2+2Пk.