Log x-1(x^2-7x+41)=2

Question

Log x-1(x^2-7x+41)=2

Answer 1

{x-1>0⇒x>1
x-1≠1⇒x≠2
{x²-7x+41>0⇒x∈R,D=-113<0<br>x∈(1;20 U (2;∞)
x²-7x+41=(x-1)²
x²-7x+41-x²+2x-1=0
-5x=-40
x=8