Решите систему X2+4y2=25 3x2+12y2=25x

Решите задачу:

$\left \{ {{x^2+4y^2=25|\cdot 3} \atop {3x^2+12y^2=25x}} \right. \; \left \{ {{3x^2+12y^2=75} \atop {3x^2+12y^2=25x}} \right. \; \ominus\; \left \{ {{75-25x=0} \atop {x^2+4y^2=25}} \right. \; \left \{ {{25x=75} \atop {x^2+4y^2=25}} \right. \\\\ \left \{ {{x=3} \atop {3^2+4y^2=25}} \right. \; \left \{ {{x=3} \atop {4y^2=16}} \right. \; \left \{ {{x=3} \atop {y^2=4}} \right. \; \left \{ {{x=3} \atop {y=\pm 2}} \right. \\\\Otvet:\; \; (3,-2)\; ,\; (3,-2).$