(6x-1)(6x+1)-(12х-5)(3х+1) при х=0,2

Question

(6x-1)(6x+1)-(12х-5)(3х+1) при х=0,2

Answer 1

36x^2-1-36x^2-12x+15x+5=0
-12+15х-1+5=0
3x+4=0
Подставляем х=0,2
3×0.2+4=0,6+4=4,6

Answer 2

36×^2-1-(2,4-5)(0,6+1)=36*(0,2)^2-(-2,6)(1,6)=1,44-(-4,16)=1,44+4,16=5,6