СРОЧНО!!! Заполните пропуски: a) (2x + ...)^2 = ... + ... + y^2 b) (3y - ...)^2 = ... -...

Question

СРОЧНО!!!
Заполните пропуски:
a) (2x + ...)^2 = ... + ... + y^2
b) (3y - ...)^2 = ... - 24y + ...
c) (... + 2m)^2 = 4n^2 + ... + ...
d) (... - ...)^2 = a^2 - ... + 9

Comments

Готово

Answer 1

А) (2×+у)^2=4×^2+4×у+у^2
б) (3у-4)^2= 9у^2-24у+16
с) (2n+2m)^2= 4n^2+8nm+4m^2
d) (a-3)^2= a^2-6a+9

Answer 2

А) (2х+у)²=4х+4ху+у² Б) (3у-8)²=9у²-24у+64 В) (2n+2m)²=4n²+8nm+4m² Г) (a-3)²=a²-6a+9